Can you use the intermediate value theorem on this fucker?

Dude face it...

Its ovah...

OH SHIT! IT'S ALGEBRA!

RED ALERT!! RED ALERT!!

EVERYBODY INTO THE ESCAPE PODS!!!

f(x) = (x-7)(x+3)

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That's all i'm gonna do

YOUR THE GUY ASKING AN ALGEBRA QUESTION ON A HENTAI WEBSITE

nerds

f(I) ⊇ [f(a), f(b)], or f(I) ⊇ [f(b), f(a)].


MACD = EMA[fast,12] - EMA[slow,26]

Are you mad?

Suppose that I is an interval [a, b] in the real numbers R and that f : I → R is a continuous function. Then the image set f(I) is also an interval, and either it contains [f(a), f(b)], or it contains [f(b), f(a)]; that is,
f(I) ⊇ [f(a), f(b)], or f(I) ⊇ [f(b), f(a)].
It is frequently stated in the following equivalent form: Suppose that f : [a, b] → R is continuous and that u is a real number satisfying f(a) < u <f> u > f(b). Then for some c ∈ [a, b], f(c) = u.
This captures an intuitive property of continuous functions: given f continuous on [1, 2], if f(1) = 3 and f(2) = 5 then f must take the value 4 somewhere between 1 and 2. It represents the idea that the graph of a continuous function on a closed interval can only be drawn without lifting your pencil from the paper.
The theorem depends on (and is actually equivalent to) the completeness of the real numbers. It is false for the rational numbers Q. For example, the function f(x) = x2 − 2 for x ∈ Q satisfies f(0) = −2 and f(2) = 2. However there is no rational number x such that f(x) = 0, because if so, then √2 would be rational.

Source: http://en.wikipedia.org/wiki/Intermediate_value_theorem
Oh Wikipedia. You so sexy

Never really did like math.

inb4 "find x" picture

Fuck you, I did it anyway.

Only equation that made sense.

Not unless they're in the kitchen or in the bedroom naked and bent over

But where are you gonna find women like that in this day and age?

No u