Homework Begging Thread

Here's me begging someone out there who can help me solve this since gah dayuuuum I suck at math and especially on logs. Pretty please?

inb4 do your own homework, lock

Edit: I just googled and found this... and lots more... http://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.313421.html

but dayum I need to know this stuff since ...finals..

^Still confused as shit. don't even know how they get that 2ab on the right side.

Is that some kind of spell chant?

no mr blaruto-san

The answer is 42. It's always 42.

7. Its probably 7. I think its 7.

What sorcery is this!? ^__^

My head. It aches so much.

Aren't logarithms like...High school stuff?

Depends on the level of math you took in high school.

I never did log, because I wanna be an accountant, I don't need some log shit

Wait, I'm gonna boot up "Number Munchers", That will have the answer.

If a² + b² = 7ab, show that Log [1/3 (a+b)] = 1/2 (Log a + Log b)...

So... (a+b)² = a² + 2ab + b² then group them into "a² + b² +2ab" and replace "a² +b²" with 7ab since the "if = 7ab" to make 7ab + 2ab... which equals 9ab...

Then... (a+b)² = 9ab... take the square root of both sides to get (a+b) = 3√ab

After that use the log properties.. then uh...

Log (a+b) = Log 3 + Log a½ + Log b½... then subtract Log 3 on both sides to get Log (a+b) - Log 3 = Log a½ + Log b½...

By using the log properties "Logь (x/y) = Logьx - Logьy" and "Logь(xy) = Logьx + Logьy" and "Logьx^r = r Logьx" I'll end up with...

Log (a+b)/3 = ½ (Log a + Log b)

[1/3 (a+b)] = (a+b)/3....

So... uh... is this it? Or do I have to solve it? It says show... and I think I showed it but I'm not sure...

I already forgot how to do these..

WHO THE HELL WROTE THAT.

They write like a girl on LSD

Im probably worse at math then anyone here. This is honestly the first time I have ever heard the word logarithm.

Doesn't mean anything to me. Just a cluster fuck of what the fuck.

I had to get a tutor in order to pass my maths because I was so bad at it.

You did great, only a bit off. It wants you to prove from
=Log[1/3 (a+b)]
and change it into
=1/2[log a +log b]

Here's how i think it should be:


Sorry for the rotation...

You're awesome. Thanks! lol

Where's that Engineering student when we need him?