math for Reps xD
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mibuchiha wrote...
Unsigned wrote...
A ball is thrown horizontally from the roof of a building 56m tall and lands 45m from the base. What is the balls initial speed?Show work.
Spoiler:
Lol, trying to calculate without any aid is quite difficult...
You just beat me to it. xD
I saw this question, solved it, and read the rest of the thread. xD
Also, since no qustion is up, here's one:
A hot air balloon is accelerating upwards at 0.5m/s^2. There is a force of 6N acting on it downwards. The balloon weighs 5kg. What is
a) the net force of the object?
b)the amount of the force acting uowards?
c)it'velocity after 10 seconds?
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mibuchiha
Fakku Elder
Lol...this one is...quite weird?
1) Upward force = 5(0.5) = 2.5N
Since the downward force is 6N...that means the net force acting on it is 3.5N directed downwards.
2) 3.5N directed downwards means -3.5N upwards.
3) I take it that the initial velocity is 0....and the balloon is at an arbitrary height from the ground. Then...after 10 seconds,
since the balloon would have a 0.7ms^-2 constant acceleration downwards....the velocity after 10s is 7m/s downwards, with its position 35m below the initial position.
all this is assuming that there's no gravity lol...
1) Upward force = 5(0.5) = 2.5N
Since the downward force is 6N...that means the net force acting on it is 3.5N directed downwards.
2) 3.5N directed downwards means -3.5N upwards.
3) I take it that the initial velocity is 0....and the balloon is at an arbitrary height from the ground. Then...after 10 seconds,
since the balloon would have a 0.7ms^-2 constant acceleration downwards....the velocity after 10s is 7m/s downwards, with its position 35m below the initial position.
all this is assuming that there's no gravity lol...
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Quadratic wrote...
mibuchiha wrote...
Unsigned wrote...
A ball is thrown horizontally from the roof of a building 56m tall and lands 45m from the base. What is the balls initial speed?Show work.
Spoiler:
Lol, trying to calculate without any aid is quite difficult...
You just beat me to it. xD
I saw this question, solved it, and read the rest of the thread. xD
Was he/she right?
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mibuchiha
Fakku Elder
@Unsigned: I was just 'eyeballing' the problem but I'm rather confident I got it right.
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mibuchiha wrote...
Lol...this one is...quite weird?1) Upward force = 5(0.5) = 2.5N
Since the downward force is 6N...that means the net force acting on it is 3.5N directed downwards.
2) 3.5N directed downwards means -3.5N upwards.
3) I take it that the initial velocity is 0....and the balloon is at an arbitrary height from the ground. Then...after 10 seconds,
since the balloon would have a 0.7ms^-2 constant acceleration downwards....the velocity after 10s is 7m/s downwards, with its position 35m below the initial position.
all this is assuming that there's no gravity lol...
Err, close, but the acceleration in c is 0.5m/s^2. Not -9.8m/s^2. xD
@Unsigned: Yeah, it's right.
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mibuchiha
Fakku Elder
Quadratic wrote...
Err, close, but the acceleration in c is 0.5m/s^2. Not -9.8m/s^2. xD
@Unsigned: Yeah, it's right.
Well, I take all three as the same problem...and I think it's weird that the upward force due to acceleration is smaller than the downward force acting on it...so the net force should be directed downwards and hence, no acceleration upwards. but in c, if you forget all thing and just take a = 0.5ms^-2, then after 10 seconds the velocity would be 5m/s....
and I'm not taking gravity into consideration in solving this lol...
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mibuchiha wrote...
Quadratic wrote...
Err, close, but the acceleration in c is 0.5m/s^2. Not -9.8m/s^2. xD
@Unsigned: Yeah, it's right.
Well, I take all three as the same problem...and I think it's weird that the upward force due to acceleration is smaller than the downward force acting on it...so the net force should be directed downwards and hence, no acceleration upwards. but in c, if you forget all thing and just take a = 0.5ms^-2, then after 10 seconds the velocity would be 5m/s....
and I'm not taking gravity into consideration in solving this lol...
Net force is the upward forces minus the downward forces. So you need to figure out the upward force that is causing it to go upwards at an acceleration of 0.5m/s.
Gravity?
wuts dat olololol Gravity doesn't matter.
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mibuchiha
Fakku Elder
oh....ok then that's easy. the force acting on the balloon would be 6N downwards and 8.5N upwards. that way the net force would be 2.5N upwards and the acceleration of the balloon is 0.5ms^-2. after 10 seconds the velocity is 5m/s upwards, if the acceleration is constant and the initial velocity is 0.
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mibuchiha
Fakku Elder
Lol, thanks. Now I got a lecture to attend...which is...urgh. Partial DE ftw!
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mibuchiha
Fakku Elder
Physics student that's going to be sucked into the weird field of theoretical physics lol...
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Here's another one, might actually be tough.
A right triangle in the first quadrant is bounded by lines y = 0, y = x, and y = -x+5. Find its area.
A right triangle in the first quadrant is bounded by lines y = 0, y = x, and y = -x+5. Find its area.
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mibuchiha wrote...
Physics student that's going to be sucked into the weird field of theoretical physics lol...For me it's Physics > Bio
there's just too mny fcking term for Bio not counting how long they are
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mibuchiha
Fakku Elder
Lol, someone did it when I took a bath...
@superior: so yo prefer to try picturing extra dimensions than to memorize terms, huh?
@superior: so yo prefer to try picturing extra dimensions than to memorize terms, huh?